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2007-10-12       - By Daevid Vincent

 Back


> -- --Original Message-- --
> From: Jay Pipes [mailto:jay@(protected)]
> Sent: Friday, October 12, 2007 2:07 PM
> To: Daevid Vincent
> Cc: mysql@(protected)
> Subject: Re: Need help with a "natural sort order" for
> version numbers and release code names
>
> Daevid Vincent wrote:
> >  
> > I'm trying to get some 'release/version numbers' to sort properly.
> >
> > mysql> SELECT ReleaseID, Name FROM releases ORDER BY Name
> DESC;        
> > +-- ---- ---+-- ---- ---- ---- ---+
> > | ReleaseID | Name                |
> > +-- ---- ---+-- ---- ---- ---- ---+
> > |        18 | Unspecified         |
> > |        20 | Next Patch          |
> > |        58 | LOCset              |
> > |        74 | Abashiri            |
> > |        54 | 4.6.0 (Folsom)      |
> >              <-- 4.5.10
> should be here
> > |        99 | 4.5.9               |
> > |        98 | 4.5.6               |
> > |        93 | 4.5.5 (Purdy)       |
> > |        97 | 4.5.4               |
> > |        96 | 4.5.3               |
> > |        94 | 4.5.2               |
> > |       100 | 4.5.10              |   <-- should be ^ there
> > |        91 | 4.5.1 Deferred      |
> > |        78 | 4.5.1 (Leavenworth) |
> > |        95 | 4.2.7.4             |
> > |        92 | 4.2.7.3             |
> > |        90 | 4.2.7.2             |
> > |        87 | 4.2.7.1             |
> > |        88 | 4.2.7.0             |  
> >
> > I like this order, especially with the top four,
> > except for that 4.5.10 should be higher up,
> > just under 4.6.0, not under 4.5.2 as it is now.
> >
> > So I tried the " + 0 " trick which makes things even worse
> > (notice the 4.2.6.1 and 4.2.6.0 -- yipes!):
> >
> > mysql> SELECT ReleaseID, Name FROM releases ORDER BY Name + 0 DESC;
>

> > +-- ---- ---+-- ---- ---- ---- ---+
> > | ReleaseID | Name                |
> > +-- ---- ---+-- ---- ---- ---- ---+
> >            
> ....(18,20,58,74) are moved
> > :(
> > |        54 | 4.6.0 (Folsom)      |
> > |        78 | 4.5.1 (Leavenworth) |
> > |       100 | 4.5.10              |
> > |        91 | 4.5.1 Deferred      |
> > |        93 | 4.5.5 (Purdy)       |
> > |        94 | 4.5.2               |
> > |        96 | 4.5.3               |
> > |        97 | 4.5.4               |
> > |        98 | 4.5.6               |
> > |        99 | 4.5.9               |
> > |        82 | 4.2.6.1             |  <<  ?
> > |        76 | 4.2.2               |
> > |        75 | 4.2.4               |
> > |        72 | 4.2.1               |
> > |        73 | 4.2.3               |
> > |        67 | 4.2.6.0             |  <<  ?
> >
> >
> > I'm pretty sure this is going to involve some sort of
> splitting the version
> > from the release codeword via some string functions, and
> then operating on that part.

> What about ORDER BY REPLACE(Name, '.', '') + 0 DESC?

Thanks for the tip Jay, but nope. It's all out of whack then.

mysql> SELECT ReleaseID, Name FROM releases ORDER BY REPLACE(Name, '.', '')
+ 0 DESC;
+-- ---- ---+-- ---- ---- ---- ---+
| ReleaseID | Name                |
+-- ---- ---+-- ---- ---- ---- ---+
|       100 | 4.5.10              |
|        95 | 4.2.7.4             |
|        92 | 4.2.7.3             |
|        90 | 4.2.7.2             |
|        87 | 4.2.7.1             |
|        88 | 4.2.7.0             |
|        86 | 4.2.6.3             |
|        83 | 4.2.6.2             |
|        82 | 4.2.6.1             |
|        67 | 4.2.6.0             |
|        85 | 4.2.5.4             |
|        84 | 4.2.5.3             |
|        80 | 4.2.5.2             |
|        79 | 4.2.5.1             |
|        54 | 4.6.0 (Folsom)      |
|        99 | 4.5.9               |
|        98 | 4.5.6               |
|        93 | 4.5.5 (Purdy)       |
|        97 | 4.5.4               |
|        96 | 4.5.3               |
|        94 | 4.5.2               |
|        91 | 4.5.1 Deferred      |
|        78 | 4.5.1 (Leavenworth) |


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