Bug: char[]s not escaped 2007-07-01 - By Andrew Sayers
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Tested against 2.2.3, mysqlpp::quote and mysqlpp::escape don't escape
text passed as an array of characters:
#include <mysql++.h>
#include <iostream>
using namespace std;
using namespace mysqlpp;
int main() {
string s1 = "Frank's Brand Hotdog Buns";
std::cout << quote << s1 << std::endl;
// Output: 'Frank\'s Brand Hotdog Buns'
char s2[] = "Frank's Brand Hotdog Buns";
std::cout << quote << s2 << std::endl;
// Output: Frank's Brand Hotdog Buns
}
C++ prefers to use the template functions rather than converting a
char[] to a char*. Here's a patch:
--- manip-old.h 2007-05-08 00:49:32.000000000 +0100
+++ manip.h 2007-07-02 01:35:45.000000000 +0100
@@ -170,6 +170,18 @@
return operator <<(o, const_cast<const char* const&>(in));
}
+inline std::ostream& operator <<(quote_type1 o,
+ char in[])
+{
+ return operator <<(o, const_cast<const char* const&>(in));
+}
+
+inline std::ostream& operator <<(quote_type1 o,
+ const char in[])
+{
+ return operator <<(o, const_cast<const char* const&>(in));
+}
+
template <>
inline std::ostream& operator <<(quote_type1 o,
@@ -540,6 +552,18 @@
return operator <<(o, const_cast<const char* const&>(in));
}
+inline std::ostream& operator <<(escape_type1 o,
+ char in[])
+{
+ return operator <<(o, const_cast<const char* const&>(in));
+}
+
+inline std::ostream& operator <<(escape_type1 o,
+ const char in[])
+{
+ return operator <<(o, const_cast<const char* const&>(in));
+}
+
/// \enum do_nothing_type0
/// \anchor do_nothing_manip
--
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