Distinct from two tables 2006-06-29 - By Peter Brawley
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Mark Steudel wrote:
> Is there a way get distinct results between pf and sf?
>
> Select
> pf.name,
> sf.name
> From
> tblpropertyfeatures,
> tblsuitefeatures
> Inner Join tblfeatures AS pf ON tblpropertyfeatures.featureid = pf.id
> Inner Join tblfeatures AS sf ON tblsuitefeatures.featureid = sf.id
>
Do you mean ...
SELECT
MIN(TableName) as TableName, id, name
FROM (
SELECT 'Table a' as TableName, a.id, a.name
FROM tblpropertyfeatures
UNION ALL
SELECT 'Table b' as TableName, b.id, b.name
FROM tblsuitefeatures
) AS tmp
GROUP BY id, name
HAVING COUNT(*) = 1
ORDER BY ID;
PB
> -- ---- ---- ---- ---- ---- ---- ---- ---
> Mark Steudel
> NetRiver
> Web and Application Developer
> 555 Dayton St.
> Suite A
> Edmonds, WA 98020
> w: http://www.netriver.net
> p: 425.741.7014
>
>
>
>
>
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Mark Steudel wrote:
<blockquote cite="mid000d01c69bc1$1785b5b0$4f00a8c0@(protected)"
type="cite">
<pre wrap="">Is there a way get distinct results between pf and sf?
Select
pf.name,
sf.name
From
tblpropertyfeatures,
tblsuitefeatures
Inner Join tblfeatures AS pf ON tblpropertyfeatures.featureid = pf.id
Inner Join tblfeatures AS sf ON tblsuitefeatures.featureid = sf.id
</pre>
</blockquote>
Do you mean ...<br>
<span>
<pre>SELECT
MIN(TableName) as TableName, id, name
FROM (
SELECT 'Table a' as TableName, a.id, a.name
FROM tblpropertyfeatures
UNION ALL
SELECT 'Table b' as TableName, b.id, b.name
FROM tblsuitefeatures
) AS tmp
GROUP BY id, name
HAVING COUNT(*) = 1
ORDER BY ID;
</pre>
</span><small>PB<br>
</small><br>
<blockquote cite="mid000d01c69bc1$1785b5b0$4f00a8c0@(protected)"
type="cite">
<pre wrap="">
-- ---- ---- ---- ---- ---- ---- ---- ---
Mark Steudel
NetRiver
Web and Application Developer
555 Dayton St.
Suite A
Edmonds, WA 98020
w: <a class="moz-txt-link-freetext" href="http://www.netriver.net">http://www
.netriver.net</a>
p: 425.741.7014
</pre>
</blockquote>
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