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Subquery help...

Subquery help...

2004-06-05       - By Josh Trutwin

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On Sat, 5 Jun 2004 19:48:44 -0600
"Daniel Isenhower " <jml@(protected) > wrote:

> This is my first email to the list, so be nice ;-)

Welcome, this is a very helpful list...

> I 'm having some difficulty with a subquery that I 'm trying to do,
> and was wondering if anyone here can shed some light on the issue...

First off, I assume you are using a version of mysql able to handle sub-queries. 4.1 or 5.0 (4.0.xx does NOT support sub-queries)

> This query returns a result as expected:
> SELECT id FROM client_list WHERE name= "Some Company "
> (the id returned here is 3)
>
> This query also returns a result as expected:
> SELECT id FROM work WHERE client_id= '3 ' ORDER BY id DESC;
>
> Does anyone know why this one doesn 't return any results?
> SELECT id FROM work WHERE client_id= '(SELECT id FROM client_list
> WHERE name= "Some Company ") ' ORDER BY id DESC;

Don 't use quotes, it 's looking for a client_id that is literally the stuff inside your quotes. I 'm guessing that 'll never be the case. :)

Try:

SELECT id FROM work WHERE client_id =
(SELECT id FROM client_list WHERE name= "Some Company ")
ORDER BY id DESC;

FWIW, this is an easy query with a JOIN:

SELECT id FROM work w
INNER JOIN client_list cl ON cl.id = w.client_id
WHERE cl.name = 'Some Company ';

Just in case you are using mysql 4.0 or earlier...

Josh

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